0=0.5x^2-3

Solution for 0=0.5x^2-3 equation:

0=0.5x^2-3

We move all terms to the left:

0-(0.5x^2-3)=0

We add all the numbers together, and all the variables

-(0.5x^2-3)=0

We get rid of parentheses

-0.5x^2+3=0

a = -0.5; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-0.5)·3
Δ = 6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6}}{2*-0.5}=\frac{0-\sqrt{6}}{-1}
=-\frac{\sqrt{}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6}}{2*-0.5}=\frac{0+\sqrt{6}}{-1}
=\frac{\sqrt{}}{-1}
$